Mutchus

The strength supply routine structure is developed as a resource of continuous present with adverse heat range coefficient. Transistor Q1 (BD 140) is used as a heat range indicator. transistor Q2 is used to avoid the strength supply from discharging through R1 when strength is out of stock. Getting routine is developed depending on the LM350 present regulator IC. The result present of the battery charger can be altered between 13-15 V by various the POT R6. LM350 will try to keep the present decrease between the feedback pin and result pin at a continuous value of 1.25V. So there will be a continuous present circulation through resistor R1. Q1 act here as a heat range indicator with the help of R6/R3/R4 elements that are more or less manages the platform present of Q1. As relationship emitter / platform of transistor Q1, the same as other semiconductors, containing the heat range coefficient of-2mV / ° C, the present result will also display a bad heat range coefficient. This one is ju...

When a discharged gel cell is connected, the charger goes into a fast charge mode at a fixed rate of 400 ma. After the chip detects the voltage leveling off or when 4 1/2 hours has elapsed. (which ever happens first.) the fast charge will stop. After the fast charge has ended, the IC goes into a trickle charge rate of about 50 ma. This trickle charge continues until 13.8 volts is reached which will stop all charging current since the cell is now fully charged. If the cell voltage should drop for any reason, either a fast charge or trickle charge (IC will detect what is needed) will start again. 12 Volt Gel Cell Charger Circuit Diagram When constructing this circuit, be sure to attach a small heat sink to Q1. Apply a DC (partially filtered) voltage of at least 15.3 volts. The voltage must never go below this level even under load conditions. Many of the DC wall transformers available will work just fine as long as they meet the minimum voltage requirement. The input voltage can be as hi...

This Circuit is used to supply 12V Circuits in the D.C rating. This circuit uses a 12V / 5A transformer. One resistor is used to reduce the current for the LED light. This circuit uses 4 diodes and 2 high uF capacitors for a clean output. 12 Volt D.C. Power Supply Circuit Diagram: By: Roger Maxwell Email: Maxwell@cwjamaica.com   

A number of people have been unable to find the transformer needed for the Black Light project, so I looked around to see if I could find a fluorescent lamp driver that does not require any special components. I finally found one in Electronics Now. Here it is. It uses a normal 120 to 6V stepdown transformer in reverse to step 12V to about 350V to drive a lamp without the need to warm the filaments. Parts: C1 100uf 25V Electrolytic Capacitor C2,C3 0.01uf 25V Ceramic Disc Capacitor C4 0.01uf 1KV Ceramic Disc Capacitor R1 1K 1/4W Resistor R2 2.7K 1/4W Resistor Q1 IRF510 MOSFET U1 TLC555 Timer IC T1 6V 300mA Transformer LAMP 4W Fluorescent Lamp MISC Board, Wire, Heatsink For Q1 Notes: Q1 must be installed on a heat sink. A 240V to 10V transformer will work better then the one in the parts list. The problem is that they are hard to find. This circuit can give a nasty (but not too dangerous) shock. Be careful around the output leads.

This adapter circuit can deliver up to 3A output voltage of 12V. The circuit can be used in cases when a current of more than 3A is required for the controller. IC regulators such high current rating are quite hard to find. The T1 transformer steps down the voltage of the rectifier bridge 12rms and D1 to produce a rectified voltage. The C1 filters the output of the rectifier produces a DC level. The passage of the series transistor Q1 (2N 3055) is biased by resistor R1 (680Ω). Since D1 is Zener breakdown region of the voltage across it is 12V. So the total output voltage of 12.7 V is constant (in theory). Zener voltage which is the most base emitter voltage of transistor Q1 Q1.Here take out the excess power needed. Notes . If 12V zener is not available ,use the nearest value. The transformer T1 can be as 23oV primary;15V/5A secondary step down transformer. The capacitors must be rated at least 25V. By changing the value of the Zener diode, different output voltages can be obtained f...

This is the Simple 50 watt 12 VDC to 220 VAC Power Inverter. Power inverter (UPS Uninterruptible power supply) is a very useful device which can convert Low voltage from a DC source to high voltage AC. The most common power inverter is 12V to 240V inverter. Perhaps that is because 12V batteries are common. This type of power inverter usually draws current from a DC battery. This battery should be able to provide a high flow of electric current.  Normally lead acid batteries can server this purpose well. This current is then converted to 240V square wave alternative current so that we may empower those electric appliances which work on 240V instead of 12V. Inverter falls in the category of expensive devices so many people don’t buy them even they need them. What if I tell you how to build an inverter (UPS Uninterruptible power supply) yourself?  Iverter circuit diagram Parts. Transformer 12+12/220 (50W) ( you can make your own inverter transformer visit Make your own homemade (...

Quickly find a reliable and cost effective a simple regulated 12 Volt power supply  Notes: This circuit above uses a 13 volt zener diode, D2 which provides the voltage regulation. Approximately 0.7 Volts are dropped across the transistors b-e junction, leaving a higher current 12.3 Volt output supply. This circuit can supply loads of up to 500 mA. This circuit is also known as an amplified zen-er circuit .  

A number of people have been unable to find the transformer needed for the Black Light project, so I looked around to see if I could find a fluorescent lamp driver that does not require any special components. I finally found one in Electronics Now. Here it is. It uses a normal 120 to 6V stepdown transformer in reverse to step 12V to about 350V to drive a lamp without the need to warm the filaments. 12 VDC Fluorescent Lamp Driver Circuit Digram Notes Q1 must be installed on a heat sink. A 240V to 10V transformer will work better then the one in the parts list.  The problem is that they are hard to find.This circuit can give a nasty (but not too dangerous) shock. Be careful around the output leads. Parts Part Total Qty. Description Substitutions C1 1 100uf 25V Electrolytic Capacitor C2,C3 2 0.01uf 25V Ceramic Disc Capacitor C4 1 0.01uf 1KV Ceramic Disc Capacitor R1 1 1K 1/4W Resistor R2 1 2.7K 1/4W Resistor Q1 1 IRF510 MOSFET U1 1 TLC555 Timer IC T1 1 6V 300mA Transformer L...