Mutchus

The circuit is devote to the radio receiver in which sound ( the gear ) is weak. With the help of this tool , which initially sounds as if far to be clearly audible. Power amplifier does not require much  electrical current source , because all components are not up to over 1 Mega . But the result was incredible because it can enhance the power of  catching the wave signal. Troubleshooting : Wether transistors placement is correct ? Placement Elco ? Check are cable . If all components have benn checked , and the damaged has been replaced . Then try , turn the potentiometer slowly and listen to how the sound output by the speaker.

This clever design uses 4 diodes in a bridge to produce a fixed voltage power supply capable of supplying 35mA. All diodes (every type of diode) are zener diodes. They all break down at a particular voltage. The fact is, a power diode breaks down at 100v or 400v and its zener characteristic is not useful.  But if we put 2 zener diodes in a bridge with two ordinary power diodes, the bridge will break-down at the voltage of the zener. This is what we have done. If we use 18v zeners, the output will be 17v4. When the incoming voltage is positive at the top, the left zener provides 18v limit (and the left power-diode produces a drop of 0.6v).  This allows the right zener to pass current just like a normal diode but the voltage available to it is just 18v.  The output of the right zener is 17v4. The same with the other half-cycle.  The current is limited by the value of the X2 capacitor and this is 7mA for each 100n when in full-wave (as per thiscircuit). We have 10 x 100...

5V to 12V CONVERTER CIRCUIT WITHOUT TRANSFORMER Make 5V battery source capable of delivering 12V. By using this circuit you can make 12Volt from a 5volt battery. It is a very useful circuit for almost all electronics applications. Most of the circuits that we discussed so far is powered by 12V battery source. Sometimes you may find difficult to get a 12V source, in such cases you can use this circuit with a 5V source. This circuit is simple to construct, cheap and efficient. Ic LT 1070 is the heart of this circuit. It is a linear Technology switching regulator, commonly used for buck boost and switching applications. The inductor L2 and capacitor C4 forms an output filter, which eliminates the excess ripple voltages from the output. From this circuit, by an input of 5V, you will get an output of about 12V, 1A. It is transformer less stepup voltage circuit. Due to the absence of transformer the circuit is compact and cheap. COMPONENTS USED IN THIS CIRCUIT C1 100mF C2 1mF C3 1000mF C4 10...